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Joules/kilogram kelvin to Btus (th)/pound/°F Converter (J/(kg·K) to Btu (th)/(lb·°F))

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Live Conversion • ISO 80000-5:2019 Certified
1 Joule/kilogram kelvin = 0.000239006 Btu (th)/pound/°F
1 J/(kg·K) = 0.000239006 Btu (th)/(lb·°F) • 1 Btu (th)/(lb·°F) = 4183.995381 J/(kg·K)
Joule/kilogram kelvin to Btu (th)/pound/°F: One Joule/kilogram kelvin is equal to 0.000239006 Btus (th)/pound/°F.
Certified Authority Value
0.00023901
Btu (th)/(lb·°F)
Exact: 1 Btu (th)/(lb·°F) ≡ 4183.9953808691 J/(kg·K)
J/(kg·K)
J/(kg·K)
Swap to Btu (th)/pound/°F to Joule/kilogram kelvin
Swap to Btu (th)/pound/°F to Joule/kilogram kelvin
Btu (th)/(lb·°F)
Btu (th)/(lb·°F) 0.000239006
Quick Values:
Conversion Formula
To convert Joule/kilogram kelvin to Btu (th)/pound/°F, multiply by 0.000239006
J/(kg·K) × 0.000239006 = Btu (th)/(lb·°F)

Calculation: 1 J/(kg·K) × 0.000239006 = 0.000239006 Btu (th)/(lb·°F)

Common Joule/kilogram kelvin to Btu (th)/pound/°F Calculations

Quick-lookup reference table showing calculated equivalents for standard increments between Joule/kilogram kelvin (J/(kg·K)) and Btu (th)/pound/°F (Btu (th)/(lb·°F)).

Tap any row to calculate
Joule/kilogram kelvin to Btu (th)/pound/°F: Primary Direct Table (15 Steps)
Joule/kilogram kelvin to Btu (th)/pound/°F Conversion Reference Table
Conversion & Equivalent Value Scientific Notation
0.001 J/(kg·K) 2.39006 × 10⁻⁷ Btu (th)/(lb·°F) 2.39 × 10⁻⁷
0.01 J/(kg·K) 2.39006 × 10⁻⁶ Btu (th)/(lb·°F) 2.39 × 10⁻⁶
0.1 J/(kg·K) 2.39006 × 10⁻⁵ Btu (th)/(lb·°F) 2.39 × 10⁻⁵
0.5 J/(kg·K) 0.000119503 Btu (th)/(lb·°F) 1.195 × 10⁻⁴
1 J/(kg·K) 0.000239006 Btu (th)/(lb·°F) 2.39 × 10⁻⁴
2 J/(kg·K) 0.000478012 Btu (th)/(lb·°F) 4.78 × 10⁻⁴
5 J/(kg·K) 0.00119503 Btu (th)/(lb·°F) 1.195 × 10⁻³
10 J/(kg·K) 0.00239006 Btu (th)/(lb·°F) 2.39 × 10⁻³
20 J/(kg·K) 0.00478012 Btu (th)/(lb·°F) 4.78 × 10⁻³
25 J/(kg·K) 0.00597515 Btu (th)/(lb·°F) 5.975 × 10⁻³
50 J/(kg·K) 0.0119503 Btu (th)/(lb·°F) 1.195 × 10⁻²
100 J/(kg·K) 0.0239006 Btu (th)/(lb·°F) 2.39 × 10⁻²
250 J/(kg·K) 0.0597515 Btu (th)/(lb·°F) 5.975 × 10⁻²
500 J/(kg·K) 0.119503 Btu (th)/(lb·°F) 1.195 × 10⁻¹
1000 J/(kg·K) 0.239006 Btu (th)/(lb·°F) 2.39 × 10⁻¹
Btu (th)/pound/°F to Joule/kilogram kelvin: Reciprocal Summary
Btu (th)/pound/°F to Joule/kilogram kelvin Conversion Reference Table
Reciprocal & Equivalent Value Scientific Notation
1 Btu (th)/(lb·°F) 4183.995381 J/(kg·K) 4.184 × 10³
5 Btu (th)/(lb·°F) 20919.976904 J/(kg·K) 2.092 × 10⁴
10 Btu (th)/(lb·°F) 41839.953809 J/(kg·K) 4.184 × 10⁴
50 Btu (th)/(lb·°F) 209199.769043 J/(kg·K) 2.092 × 10⁵
100 Btu (th)/(lb·°F) 418399.538087 J/(kg·K) 4.184 × 10⁵
View Complete 15-Row Btu (th)/pound/°F to Joule/kilogram kelvin Table

Real-World Context & Everyday Benchmarks

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To help contextualize these units in everyday life, science, and engineering, here are verified real-world reference points for Joule/kilogram kelvin (J/(kg·K)) and Btu (th)/pound/°F (Btu (th)/(lb·°F)):

Joule/kilogram kelvin References:

  • Pure liquid water standard specific heat capacity at 25°C 4184 J/(kg·K)
  • Dry atmospheric air specific heat at constant pressure cp 1005 J/(kg·K)
  • Solid structural aluminum metal specific heat capacity 897 J/(kg·K)
  • Pure electrical copper metal specific heat capacity 385 J/(kg·K)
  • Dense lead metal element low specific heat capacity 129 J/(kg·K)

Btu (th)/pound/°F References:

  • Thermochemical BTU standard specific heat for water 1 Btu (th)/(lb·°F)

Tap any benchmark above to automatically calculate its exact equivalent in Btu (th)/pound/°F.

ISQ Dimension: [L² T⁻² Θ⁻¹] Coherent SI Unit: joule per kilogram kelvin (J/(kg·K)) Thermodynamics & Heat Transfer

How to Convert Joule/kilogram kelvin to Btu (th)/pound/°F

Converting Joule/kilogram kelvin (J/(kg·K)) to Btu (th)/pound/°F (Btu (th)/(lb·°F)) is a core calculation in Specific Heat Capacity, which measures the thermal energy required to raise the temperature of a unit mass of substance by one degree. This calculation navigates the boundary between the International Metric System (SI) and British Imperial / US Customary engineering standards. In contemporary metrology, Imperial units are defined in terms of exact SI standards via international agreements—notably NIST SP 811 and the 1959 International Yard and Pound Agreement. Exactly 1 Joule/kilogram kelvin equals 0.000239006 Btu (th)/pound/°F, while 1 Btu (th)/(lb·°F) equals 4183.995381 J/(kg·K).

Direct Factor1 J/(kg·K) = 0.000239006 Btu (th)/(lb·°F)
Inverse Ratio1 Btu (th)/(lb·°F) = 4183.995381 J/(kg·K)
Conversion ScaleMetric SI to British Imperial / US Customary Bridge
First-Principles SI Derivation ProofNIST SP 811 / ISO 80000 Compliance

Mathematical Conversion Derivation via Coherent SI Base Unit

Under the International System of Quantities (ISQ), dimensional conversion between non-SI units is rigorously resolved by bridging through the coherent SI base unit (joule per kilogram kelvin (J/(kg·K))) without arbitrary rounding:

Vtarget=Vsource×(ksource→SIktarget→SI)V_{\text{target}} = V_{\text{source}} \times \left( \frac{k_{\text{source} \to \text{SI}}}{k_{\text{target} \to \text{SI}}} \right)
Universal Dimensional Conversion Law (ISO 80000 / NIST SP 811)
1. Source SI Bridge (ksource):1 J/(kg·K) = 1 joule per kilogram kelvin (J/(kg·K))
2. Target SI Bridge (ktarget):1 Btu (th)/(lb·°F) = 4183.995381 joule per kilogram kelvin (J/(kg·K))
Step-by-step substitution for Joule/kilogram kelvin → Btu (th)/pound/°F:V(Btu (th)/(lb·°F)) = V(J/(kg·K)) × ( 1 / 4183.995381 ) = V(J/(kg·K)) × 0.000239006
Mathematical FormulaValue in Btu (th)/pound/°F = Value in Joule/kilogram kelvin × 0.000239006Direct computational formula applied for standard conversion.
Worked Example

For an engineering input of 15 J/(kg·K), applying the conversion factor yields exactly 0.00358509 Btu (th)/(lb·°F). At larger operational scale, 240 Joule/kilogram kelvin corresponds to 0.0573614 Btu (th)/(lb·°F).

Inverse check: 1 Btu (th)/(lb·°F) = 4183.995381 J/(kg·K).

Understanding Joule/kilogram kelvin and Btu (th)/pound/°F

Joule/kilogram kelvin

J/(kg·K)
SI Base Standard

A Joule/kilogram kelvin (J/(kg·K)) is the official base standard unit for specific heat capacity.

Applications & Practical Context

In practical specific heat capacity terms, a pure liquid water standard specific heat capacity at 25°C equals 4184 J/(kg·K), a dry atmospheric air specific heat at constant pressure cp equals 1005 J/(kg·K), a solid structural aluminum metal specific heat capacity equals 897 J/(kg·K).

Physical Setup

A specific heat capacity of 1 J/(kg·K) means 1 Joule/kilogram kelvin of heat energy changes the temperature of 1 unit mass by 1 degree.

Conversion to SI Unit: joule per kilogram kelvin (J/(kg·K))
1 J/(kg·K) = 1 J/(kg·K) (Base Standard)

Btu (th)/pound/°F

Btu (th)/(lb·°F)
Imperial / US

A Btu (th)/pound/°F (Btu (th)/(lb·°F)) is an imperial and US customary unit for specific heat capacity.

Applications & Practical Context

In practical specific heat capacity terms, a thermochemical BTU standard specific heat for water equals 1 Btu (th)/(lb·°F).

Physical Setup

A physical magnitude of 1 Btu (th)/(lb·°F) corresponds to 4183.995381 J/(kg·K) in standard SI measurement.

Conversion to SI Unit: joule per kilogram kelvin (J/(kg·K))
1 Btu (th)/(lb·°F) = 4183.995381 J/(kg·K)

Domain Metrology & Engineering Applications

Governing Law & Equation

Specific Enthalpy Derivative (c_p = (∂h/∂T)_p)

Measurement Instrumentation

Rigorously quantified in laboratory and field settings using differential scanning calorimeters (DSC), adiabatic drop calorimeters, and dual-furnace calorimeter systems.

Primary Industry Sectors

Applied across battery thermal runaway mitigation (EV cell modeling), chemical synthesis reactor safety, molten salt solar storage, and cryogenic coolant engineering under international metrology standard ISO 80000-5:2019, NIST Chemistry WebBook.

Institutional Metrology & Standard Authority:

Formulas, conversion coefficients, and base definitions on this page strictly adhere to the ISO 80000-5:2019, NIST Chemistry WebBook and the BIPM SI Brochure (9th Edition). Governed by Specific Enthalpy Derivative (c_p = (∂h/∂T)_p) under ISO 80000 dimensional vector [L² T⁻² Θ⁻¹].

Multi-Variable Engineering Bridge Thermodynamics & Heat Storage

Specific Heat Capacity to Thermal Energy Storage Bridge (Joules • Kilojoules • Megajoules • kWh • BTU)

Calculate total sensible thermal storage energy Q = c_p × (m × ΔT) for heating or cooling mass charges, bridging specific heat capacity [L² T⁻² Θ⁻¹] with stored thermal energy [M L² T⁻²].

Q = c_p × (m × ΔT)
Vector: [J/(kg·K)] × [kg·K] → [J]
Live Calculated Bridge Equivalent:
1 J/(kg·K) at 50 kg Domestic Water at 40K Swing (2,000 kg·K) = 2000 J
Equals 2 kJ • 0.002 MJ • 0.00055556 kWh
SI Energy
2000
J
Joules
Thermal Scale
2
kJ
Kilojoules
Bulk Energy
0.002
MJ
Megajoules
Electric Utility Meter
0.00055556
kWh
Kilowatt-Hours
Battery Capacity
0.5556
Wh
Watt-Hours
Imperial Thermal
1.8956
BTU
British Thermal Units
  1. 1. Normalize Input to SI Base Unit (J/(kg·K)):
    c_p = 1 J/(kg·K) × 1 = 1 J/(kg·K)
  2. 2. Apply Engineering Parameter (mΔT):
    Selected condition: 50 kg Domestic Water at 40K Swing (2,000 kg·K) at mΔT = 2000 kg·K
  3. 3. Execute Governing Physical Law in SI Units:
    Q = c_p × (m × ΔT) = (1 J/(kg·K)) × (2000 kg·K) = 2000 J
  4. 4. Convert to Standard Engineering Units:
    • J: 2000 × 1 = 2000 J (Joules) • kJ: 2000 × 0.001 = 2 kJ (Kilojoules) • MJ: 2000 × 1 × 10⁻⁶ = 0.002 MJ (Megajoules) • kWh: 2000 × 2.7778 × 10⁻⁷ = 0.00055556 kWh (Kilowatt-Hours) • Wh: 2000 × 0.0002778 = 0.5556 Wh (Watt-Hours) • BTU: 2000 × 0.0009478 = 1.8956 BTU (British Thermal Units)
Explore Full Energy Converter →
Engineering Substance / Operating Standard Parameter Value (kg·K) Reference State / Condition Typical Industrial & Engineering Application
50 kg Domestic Water at 40K Swing (2,000 kg·K) 2000 m = 50 kg, ΔT = 40 K 50-liter domestic hot water tank charge
1,000 kg Hydronic Buffer at 20K Swing (20,000 kg·K) 20000 m = 1,000 kg, ΔT = 20 K Commercial heat pump thermal buffer storage
200 kg Engine Block at 70K Swing (14,000 kg·K) 14000 m = 200 kg, ΔT = 70 K Cast iron engine warm-up heat soak
10,000 kg Process Fluid at 50K Swing (500,000 kg·K) 500000 m = 10,000 kg, ΔT = 50 K Industrial batch chemical reactor heat load
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Frequently Asked Questions

There are exactly 0.000239006 btus (th)/pound/°f (Btu (th)/(lb·°F)) in 1 joule/kilogram kelvin (J/(kg·K)). To calculate larger amounts manually, simply multiply your total number of joules/kilogram kelvin by the conversion multiplier of 0.000239006.

The mathematical formula to convert joules/kilogram kelvin to btus (th)/pound/°f is: [value] * 0.000239006 = btus (th)/pound/°f. Rather than doing the math manually, you can use our high-precision online calculator to process this exact equation instantly without rounding errors.

To perform the reverse calculation from btus (th)/pound/°f back to joules/kilogram kelvin, you must divide your starting value by 0.000239006. Our bidirectional tool automatically computes this inverse equation the moment you type into the btu (th)/pound/°f input field.

1 Btu (th)/pound/°F is larger than 1 Joule/kilogram kelvin. Specifically, 1 Joule/kilogram kelvin equals 0.000239006 btus (th)/pound/°f, meaning 1 Btu (th)/pound/°F is 4183.9954 times larger than 1 Joule/kilogram kelvin (a difference of 3.62 orders of magnitude). Expressing measurements in joules/kilogram kelvin requires a larger numerical value to represent the equivalent physical magnitude.

Under standard international measurement guidelines, 1 Joule/kilogram kelvin converts to 0.000239006 btus (th)/pound/°f. Precise numerical conversion factors ensure consistency across laboratory, engineering, and field data.