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Calories (it)/gram/K to Btus (th)/pound/°F Converter (cal/(g·K) to Btu (th)/(lb·°F))

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Live Conversion • ISO 80000-5:2019 Certified
1 Calorie (IT)/gram/K = 1.00066989 Btu (th)/pound/°F
1 cal/(g·K) = 1.00067 Btu (th)/(lb·°F) • 1 Btu (th)/(lb·°F) = 0.999331 cal/(g·K)
Calorie (IT)/gram/K to Btu (th)/pound/°F: One Calorie (IT)/gram/K is equal to 1.00066989 Btus (th)/pound/°F.
Certified Authority Value
1.00066989
Btu (th)/(lb·°F)
Exact: 1 Btu (th)/(lb·°F) ≡ 0.9993305607 cal/(g·K)
cal/(g·K)
cal/(g·K)
Swap to Btu (th)/pound/°F to Calorie (IT)/gram/K
Swap to Btu (th)/pound/°F to Calorie (IT)/gram/K
Btu (th)/(lb·°F)
Btu (th)/(lb·°F) 1.00066989
Quick Values:
Conversion Formula
To convert Calorie (IT)/gram/K to Btu (th)/pound/°F, multiply by 1.00066989
cal/(g·K) × 1.00066989 = Btu (th)/(lb·°F)

Calculation: 1 cal/(g·K) × 1.00066989 = 1.00066989 Btu (th)/(lb·°F)

Common Calorie (IT)/gram/K to Btu (th)/pound/°F Calculations

Quick-lookup reference table showing calculated equivalents for standard increments between Calorie (IT)/gram/K (cal/(g·K)) and Btu (th)/pound/°F (Btu (th)/(lb·°F)).

Tap any row to calculate
Calorie (IT)/gram/K to Btu (th)/pound/°F: Primary Direct Table (15 Steps)
Calorie (IT)/gram/K to Btu (th)/pound/°F Conversion Reference Table
Conversion & Equivalent Value Scientific Notation
0.001 cal/(g·K) 0.00100067 Btu (th)/(lb·°F) 1.001 × 10⁻³
0.01 cal/(g·K) 0.0100067 Btu (th)/(lb·°F) 1.001 × 10⁻²
0.1 cal/(g·K) 0.100067 Btu (th)/(lb·°F) 1.001 × 10⁻¹
0.5 cal/(g·K) 0.500335 Btu (th)/(lb·°F) 5.003 × 10⁻¹
1 cal/(g·K) 1.00067 Btu (th)/(lb·°F) 1.001 × 10⁰
2 cal/(g·K) 2.00134 Btu (th)/(lb·°F) 2.001 × 10⁰
5 cal/(g·K) 5.003349 Btu (th)/(lb·°F) 5.003 × 10⁰
10 cal/(g·K) 10.006699 Btu (th)/(lb·°F) 1.001 × 10¹
20 cal/(g·K) 20.013398 Btu (th)/(lb·°F) 2.001 × 10¹
25 cal/(g·K) 25.016747 Btu (th)/(lb·°F) 2.502 × 10¹
50 cal/(g·K) 50.033494 Btu (th)/(lb·°F) 5.003 × 10¹
100 cal/(g·K) 100.066989 Btu (th)/(lb·°F) 1.001 × 10²
250 cal/(g·K) 250.167472 Btu (th)/(lb·°F) 2.502 × 10²
500 cal/(g·K) 500.334944 Btu (th)/(lb·°F) 5.003 × 10²
1000 cal/(g·K) 1000.669888 Btu (th)/(lb·°F) 1.001 × 10³
Btu (th)/pound/°F to Calorie (IT)/gram/K: Reciprocal Summary
Btu (th)/pound/°F to Calorie (IT)/gram/K Conversion Reference Table
Reciprocal & Equivalent Value Scientific Notation
1 Btu (th)/(lb·°F) 0.999331 cal/(g·K) 9.993 × 10⁻¹
5 Btu (th)/(lb·°F) 4.996653 cal/(g·K) 4.997 × 10⁰
10 Btu (th)/(lb·°F) 9.993306 cal/(g·K) 9.993 × 10⁰
50 Btu (th)/(lb·°F) 49.966528 cal/(g·K) 4.997 × 10¹
100 Btu (th)/(lb·°F) 99.933056 cal/(g·K) 9.993 × 10¹
View Complete 15-Row Btu (th)/pound/°F to Calorie (IT)/gram/K Table

Real-World Context & Everyday Benchmarks

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To help contextualize these units in everyday life, science, and engineering, here are verified real-world reference points for Calorie (IT)/gram/K (cal/(g·K)) and Btu (th)/pound/°F (Btu (th)/(lb·°F)):

Calorie (IT)/gram/K References:

  • Liquid water specific heat capacity relative to Kelvin 1 cal/(g·K)

Btu (th)/pound/°F References:

  • Thermochemical BTU standard specific heat for water 1 Btu (th)/(lb·°F)

Tap any benchmark above to automatically calculate its exact equivalent in Btu (th)/pound/°F.

ISQ Dimension: [L² T⁻² Θ⁻¹] Coherent SI Unit: joule per kilogram kelvin (J/(kg·K)) Thermodynamics & Heat Transfer

How to Convert Calorie (IT)/gram/K to Btu (th)/pound/°F

Converting Calorie (IT)/gram/K (cal/(g·K)) to Btu (th)/pound/°F (Btu (th)/(lb·°F)) is a core calculation in Specific Heat Capacity, which measures the thermal energy required to raise the temperature of a unit mass of substance by one degree. This calculation navigates the boundary between the International Metric System (SI) and British Imperial / US Customary engineering standards. In contemporary metrology, Imperial units are defined in terms of exact SI standards via international agreements—notably NIST SP 811 and the 1959 International Yard and Pound Agreement. Exactly 1 Calorie (IT)/gram/K equals 1.00067 Btu (th)/pound/°F, while 1 Btu (th)/(lb·°F) equals 0.999331 cal/(g·K).

Direct Factor1 cal/(g·K) = 1.00067 Btu (th)/(lb·°F)
Inverse Ratio1 Btu (th)/(lb·°F) = 0.999331 cal/(g·K)
Conversion ScaleMetric SI to British Imperial / US Customary Bridge
First-Principles SI Derivation ProofNIST SP 811 / ISO 80000 Compliance

Mathematical Conversion Derivation via Coherent SI Base Unit

Under the International System of Quantities (ISQ), dimensional conversion between non-SI units is rigorously resolved by bridging through the coherent SI base unit (joule per kilogram kelvin (J/(kg·K))) without arbitrary rounding:

Vtarget=Vsource×(ksource→SIktarget→SI)V_{\text{target}} = V_{\text{source}} \times \left( \frac{k_{\text{source} \to \text{SI}}}{k_{\text{target} \to \text{SI}}} \right)
Universal Dimensional Conversion Law (ISO 80000 / NIST SP 811)
1. Source SI Bridge (ksource):1 cal/(g·K) = 4186.798188 joule per kilogram kelvin (J/(kg·K))
2. Target SI Bridge (ktarget):1 Btu (th)/(lb·°F) = 4183.995381 joule per kilogram kelvin (J/(kg·K))
Step-by-step substitution for Calorie (IT)/gram/K → Btu (th)/pound/°F:V(Btu (th)/(lb·°F)) = V(cal/(g·K)) × ( 4186.798188 / 4183.995381 ) = V(cal/(g·K)) × 1.00067
Mathematical FormulaValue in Btu (th)/pound/°F = Value in Calorie (IT)/gram/K × 1.00066989Direct computational formula applied for standard conversion.
Worked Example

Evaluating an input of 24 Calorie (IT)/gram/K (cal/(g·K)) produces 24.016077 Btu (th)/pound/°F (Btu (th)/(lb·°F)). In heavy-duty utility and industrial workloads, 10000 cal/(g·K) equals 10006.698877 Btu (th)/(lb·°F).

Inverse check: 1 Btu (th)/(lb·°F) = 0.999331 cal/(g·K).

Understanding Calorie (IT)/gram/K and Btu (th)/pound/°F

Calorie (IT)/gram/K

cal/(g·K)
Standard Unit

A Calorie (IT)/gram/K (cal/(g·K)) is a recognized unit for specific heat capacity.

Applications & Practical Context

In practical specific heat capacity terms, a liquid water specific heat capacity relative to Kelvin equals 1 cal/(g·K).

Physical Setup

A physical magnitude of 1 cal/(g·K) corresponds to 4186.798188 J/(kg·K) in standard SI measurement.

Conversion to SI Unit: joule per kilogram kelvin (J/(kg·K))
1 cal/(g·K) = 4186.798188 J/(kg·K)

Btu (th)/pound/°F

Btu (th)/(lb·°F)
Imperial / US

A Btu (th)/pound/°F (Btu (th)/(lb·°F)) is an imperial and US customary unit for specific heat capacity.

Applications & Practical Context

In practical specific heat capacity terms, a thermochemical BTU standard specific heat for water equals 1 Btu (th)/(lb·°F).

Physical Setup

A physical magnitude of 1 Btu (th)/(lb·°F) corresponds to 4183.995381 J/(kg·K) in standard SI measurement.

Conversion to SI Unit: joule per kilogram kelvin (J/(kg·K))
1 Btu (th)/(lb·°F) = 4183.995381 J/(kg·K)

Domain Metrology & Engineering Applications

Governing Law & Equation

Specific Enthalpy Derivative (c_p = (∂h/∂T)_p)

Measurement Instrumentation

Rigorously quantified in laboratory and field settings using differential scanning calorimeters (DSC), adiabatic drop calorimeters, and dual-furnace calorimeter systems.

Primary Industry Sectors

Applied across battery thermal runaway mitigation (EV cell modeling), chemical synthesis reactor safety, molten salt solar storage, and cryogenic coolant engineering under international metrology standard ISO 80000-5:2019, NIST Chemistry WebBook.

Institutional Metrology & Standard Authority:

Formulas, conversion coefficients, and base definitions on this page strictly adhere to the ISO 80000-5:2019, NIST Chemistry WebBook and the BIPM SI Brochure (9th Edition). Governed by Specific Enthalpy Derivative (c_p = (∂h/∂T)_p) under ISO 80000 dimensional vector [L² T⁻² Θ⁻¹].

Multi-Variable Engineering Bridge Thermodynamics & Heat Storage

Specific Heat Capacity to Thermal Energy Storage Bridge (Joules • Kilojoules • Megajoules • kWh • BTU)

Calculate total sensible thermal storage energy Q = c_p × (m × ΔT) for heating or cooling mass charges, bridging specific heat capacity [L² T⁻² Θ⁻¹] with stored thermal energy [M L² T⁻²].

Q = c_p × (m × ΔT)
Vector: [J/(kg·K)] × [kg·K] → [J]
Live Calculated Bridge Equivalent:
1 cal/(g·K) at 50 kg Domestic Water at 40K Swing (2,000 kg·K) = 8373596.3759 J
Equals 8373.5964 kJ • 8.373596 MJ • 2.325999 kWh
SI Energy
8373596.3759
J
Joules
Thermal Scale
8373.5964
kJ
Kilojoules
Bulk Energy
8.373596
MJ
Megajoules
Electric Utility Meter
2.325999
kWh
Kilowatt-Hours
Battery Capacity
2325.999
Wh
Watt-Hours
Imperial Thermal
7936.638
BTU
British Thermal Units
  1. 1. Normalize Input to SI Base Unit (J/(kg·K)):
    c_p = 1 cal/(g·K) × 4186.79818795 = 4186.79818795 J/(kg·K)
  2. 2. Apply Engineering Parameter (mΔT):
    Selected condition: 50 kg Domestic Water at 40K Swing (2,000 kg·K) at mΔT = 2000 kg·K
  3. 3. Execute Governing Physical Law in SI Units:
    Q = c_p × (m × ΔT) = (4186.79818795 J/(kg·K)) × (2000 kg·K) = 8373596.375907 J
  4. 4. Convert to Standard Engineering Units:
    • J: 8373596.375907 × 1 = 8373596.3759 J (Joules) • kJ: 8373596.375907 × 0.001 = 8373.5964 kJ (Kilojoules) • MJ: 8373596.375907 × 1 × 10⁻⁶ = 8.373596 MJ (Megajoules) • kWh: 8373596.375907 × 2.7778 × 10⁻⁷ = 2.325999 kWh (Kilowatt-Hours) • Wh: 8373596.375907 × 0.0002778 = 2325.999 Wh (Watt-Hours) • BTU: 8373596.375907 × 0.0009478 = 7936.638 BTU (British Thermal Units)
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Engineering Substance / Operating Standard Parameter Value (kg·K) Reference State / Condition Typical Industrial & Engineering Application
50 kg Domestic Water at 40K Swing (2,000 kg·K) 2000 m = 50 kg, ΔT = 40 K 50-liter domestic hot water tank charge
1,000 kg Hydronic Buffer at 20K Swing (20,000 kg·K) 20000 m = 1,000 kg, ΔT = 20 K Commercial heat pump thermal buffer storage
200 kg Engine Block at 70K Swing (14,000 kg·K) 14000 m = 200 kg, ΔT = 70 K Cast iron engine warm-up heat soak
10,000 kg Process Fluid at 50K Swing (500,000 kg·K) 500000 m = 10,000 kg, ΔT = 50 K Industrial batch chemical reactor heat load
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Frequently Asked Questions

There are exactly 1.00066989 btus (th)/pound/°f (Btu (th)/(lb·°F)) in 1 calorie (it)/gram/k (cal/(g·K)). To calculate larger amounts manually, simply multiply your total number of calories (it)/gram/k by the conversion multiplier of 1.00066989.

The mathematical formula to convert calories (it)/gram/k to btus (th)/pound/°f is: [value] * 1.00066989 = btus (th)/pound/°f. Rather than doing the math manually, you can use our high-precision online calculator to process this exact equation instantly without rounding errors.

To perform the reverse calculation from btus (th)/pound/°f back to calories (it)/gram/k, you must divide your starting value by 1.00066989. Our bidirectional tool automatically computes this inverse equation the moment you type into the btu (th)/pound/°f input field.

1 Calorie (IT)/gram/K is larger than 1 Btu (th)/pound/°F. Specifically, 1 Calorie (IT)/gram/K equals exactly 1.00066989 btus (th)/pound/°f, making it 1.0007 times larger (a difference of 0.00 orders of magnitude). Therefore, quantities expressed in btus (th)/pound/°f require a larger numerical value to represent the same physical amount.

Under standard international measurement guidelines, 1 Calorie (IT)/gram/K converts to 1.00066989 btus (th)/pound/°f. Precise numerical conversion factors ensure consistency across laboratory, engineering, and field data.