Pounds/foot/hour to Poundal Seconds/square foot Converter (lb/(ft·h) to pdl·s/ft²)
lb/(ft·h) × 0.00027777778 = pdl·s/ft²
Calculation: 1 lb/(ft·h) × 0.00027777778 = 0.00027777778 pdl·s/ft²
Common Pound/foot/hour to Poundal second/square foot Calculations
Quick-lookup reference table showing calculated equivalents for standard increments between Pound/foot/hour (lb/(ft·h)) and Poundal second/square foot (pdl·s/ft²).
| Conversion & Equivalent Value | Scientific Notation |
|---|---|
| 0.001 lb/(ft·h) 2.777778 × 10⁻⁷ pdl·s/ft² | 2.778 × 10⁻⁷ |
| 0.01 lb/(ft·h) 2.777778 × 10⁻⁶ pdl·s/ft² | 2.778 × 10⁻⁶ |
| 0.1 lb/(ft·h) 2.777778 × 10⁻⁵ pdl·s/ft² | 2.778 × 10⁻⁵ |
| 0.5 lb/(ft·h) 0.000138889 pdl·s/ft² | 1.389 × 10⁻⁴ |
| 1 lb/(ft·h) 0.000277778 pdl·s/ft² | 2.778 × 10⁻⁴ |
| 2 lb/(ft·h) 0.000555556 pdl·s/ft² | 5.556 × 10⁻⁴ |
| 5 lb/(ft·h) 0.00138889 pdl·s/ft² | 1.389 × 10⁻³ |
| 10 lb/(ft·h) 0.00277778 pdl·s/ft² | 2.778 × 10⁻³ |
| 20 lb/(ft·h) 0.00555556 pdl·s/ft² | 5.556 × 10⁻³ |
| 25 lb/(ft·h) 0.00694444 pdl·s/ft² | 6.944 × 10⁻³ |
| 50 lb/(ft·h) 0.0138889 pdl·s/ft² | 1.389 × 10⁻² |
| 100 lb/(ft·h) 0.0277778 pdl·s/ft² | 2.778 × 10⁻² |
| 250 lb/(ft·h) 0.0694444 pdl·s/ft² | 6.944 × 10⁻² |
| 500 lb/(ft·h) 0.138889 pdl·s/ft² | 1.389 × 10⁻¹ |
| 1000 lb/(ft·h) 0.277778 pdl·s/ft² | 2.778 × 10⁻¹ |
| Reciprocal & Equivalent Value | Scientific Notation |
|---|---|
| 1 pdl·s/ft² 3600 lb/(ft·h) | 3.6 × 10³ |
| 5 pdl·s/ft² 18000 lb/(ft·h) | 1.8 × 10⁴ |
| 10 pdl·s/ft² 36000 lb/(ft·h) | 3.6 × 10⁴ |
| 50 pdl·s/ft² 180000 lb/(ft·h) | 1.8 × 10⁵ |
| 100 pdl·s/ft² 360000 lb/(ft·h) | 3.6 × 10⁵ |
Real-World Context & Everyday Benchmarks
Tap to load into converterTo help contextualize these units in everyday life, science, and engineering, here are verified real-world reference points for Pound/foot/hour (lb/(ft·h)) and Poundal second/square foot (pdl·s/ft²):
Pound/foot/hour References:
- Chemical engineering pipe fluid friction calculations for oil 200 lb/(ft·h)
Poundal second/square foot References:
- Imperial physics calculation: Lubricating oil shear viscosity 0.05 pdl·s/ft²
How to Convert Pound/foot/hour to Poundal second/square foot
Converting Pound/foot/hour (lb/(ft·h)) to Poundal second/square foot (pdl·s/ft²) is a core calculation in Dynamic Viscosity, which quantifies a fluid's internal tangential resistance to shear deformation and laminar flow. This calculation navigates the boundary between the International Metric System (SI) and British Imperial / US Customary engineering standards. In contemporary metrology, Imperial units are defined in terms of exact SI standards via international agreements—notably NIST SP 811 and the 1959 International Yard and Pound Agreement. Exactly 1 Pound/foot/hour equals 0.000277778 Poundal second/square foot, while 1 pdl·s/ft² equals 3600 lb/(ft·h).
Mathematical Conversion Derivation via Coherent SI Base Unit
Under the International System of Quantities (ISQ), dimensional conversion between non-SI units is rigorously resolved by bridging through the coherent SI base unit (pascal second (Pa·s)) without arbitrary rounding:
1 lb/(ft·h) = 0.000413379 pascal second (Pa·s)1 pdl·s/ft² = 1.488164 pascal second (Pa·s)V(pdl·s/ft²) = V(lb/(ft·h)) × ( 0.000413379 / 1.488164 ) = V(lb/(ft·h)) × 0.000277778Value in Poundal second/square foot = Value in Pound/foot/hour × 0.00027777778Direct computational formula applied for standard conversion.To convert 120 Pound/foot/hour (lb/(ft·h)) to Poundal second/square foot (pdl·s/ft²): multiply 120 by 0.000277778 to get 0.0333333 pdl·s/ft². At an industrial engineering scale, 1000 lb/(ft·h) converts to 0.277778 pdl·s/ft².
Inverse check: 1 pdl·s/ft² = 3600 lb/(ft·h).Understanding Pound/foot/hour and Poundal second/square foot
Pound/foot/hour
lb/(ft·h)A Pound/foot/hour (lb/(ft·h)) is an imperial and US customary unit for dynamic viscosity.
Applications & Practical Context
In practical viscosity dynamic terms, a chemical engineering pipe fluid friction calculations for oil equals 200 lb/(ft·h).
A physical magnitude of 1 lb/(ft·h) corresponds to 0.000413379 Pa·s in standard SI measurement.
1 lb/(ft·h) = 0.000413379 Pa·sPoundal second/square foot
pdl·s/ft²A Poundal second/square foot (pdl·s/ft²) is an imperial and US customary unit for dynamic viscosity.
Applications & Practical Context
In practical viscosity dynamic terms, a imperial physics calculation: Lubricating oil shear viscosity equals 0.05 pdl·s/ft².
A physical magnitude of 1 pdl·s/ft² corresponds to 1.488164 Pa·s in standard SI measurement.
1 pdl·s/ft² = 1.488164 Pa·sDomain Metrology & Engineering Applications
Newton's Law of Viscosity (τ = μ · du/dy)
Rigorously quantified in laboratory and field settings using rotational cone-and-plate rheometers, falling ball Höppler viscometers, and vibrating wire viscometers.
Applied across lubricating oil tribology (SAE engine grades), polymer extrusion, paint and coating formulation, and pharmaceutical liquid processing under international metrology standard ISO 80000-4:2019, ASTM D445.
Formulas, conversion coefficients, and base definitions on this page strictly adhere to the ISO 80000-4:2019, ASTM D445 and the BIPM SI Brochure (9th Edition). Governed by Newton's Law of Viscosity (τ = μ · du/dy) under ISO 80000 dimensional vector [M L⁻¹ T⁻¹].
Dynamic to Kinematic Viscosity Bridge (m²/s • cSt • Stokes • ft²/s • in²/s • mm²/s)
Calculate fluid kinematic momentum diffusivity ν = μ / ρ across process liquids, bridging dynamic viscosity [M L⁻¹ T⁻¹] and kinematic viscosity [L² T⁻¹] via metrological density (ρ).
ν = μ / ρ
[Pa·s] ÷ [kg/m³] → [m²/s]
-
1. Normalize Input to SI Base Unit (Pa·s):
μ = 1 lb/(ft·h) × 0.00041338 = 0.00041338 Pa·s -
2. Apply Engineering Parameter (ρ):
Selected condition: Engine Lubricating Oil (SAE 30, 20°C) at ρ = 885 kg/m³ -
3. Execute Governing Physical Law in SI Units:
ν = μ / ρ = (0.00041338 Pa·s) ÷ (885 kg/m³) = 4.670948 × 10⁻⁷ m²/s -
4. Convert to Standard Engineering Units:
• m²/s: 4.670948 × 10⁻⁷ × 1 = 4.670948 × 10⁻⁷ m²/s (Square Meters per Second) • cSt: 4.670948 × 10⁻⁷ × 1000000 = 0.4671 cSt (Centistokes) • St: 4.670948 × 10⁻⁷ × 10000 = 0.004671 St (Stokes) • ft²/s: 4.670948 × 10⁻⁷ × 10.7639 = 5.0278 × 10⁻⁶ ft²/s (Square Feet per Second) • in²/s: 4.670948 × 10⁻⁷ × 1550.0031 = 0.00072 in²/s (Square Inches per Second) • mm²/s: 4.670948 × 10⁻⁷ × 1000000 = 0.4671 mm²/s (Square Millimeters per Second)
| Engineering Substance / Operating Standard | Parameter Value (kg/m³) | Reference State / Condition | Typical Industrial & Engineering Application |
|---|---|---|---|
| Water (20°C / Standard Ambient) | 998.2 |
998.2 kg/m³ | Hydronic HVAC & cooling water (NIST) |
| Engine Lubricating Oil (SAE 30, 20°C) | 885 |
885.0 kg/m³ | Crankcase lubrication & turbo bearing feeds |
| Hydraulic Oil (ISO VG 46, 20°C) | 870 |
870.0 kg/m³ | Industrial hydraulic systems & servo controls |
| Heavy Fuel Oil (Bunker C / HFO, 50°C) | 920 |
920.0 kg/m³ | Marine diesel engines & power plant burners |
| Pure Glycerol (100% C₃H₈O₃, 20°C) | 1260 |
1,260.0 kg/m³ | High-viscosity metrology reference fluid |
Frequently Asked Questions
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