Kilocalories (th)/kilogram/°C to Calories (it)/gram/°F Converter (kcal (th)/(kg·°C) to cal/(g·°F))
kcal (th)/(kg·°C) × 1.79879622 = cal/(g·°F)
Calculation: 1 kcal (th)/(kg·°C) × 1.79879622 = 1.79879622 cal/(g·°F)
Common Kilocalorie (th)/kilogram/°C to Calorie (IT)/gram/°F Calculations
Quick-lookup reference table showing calculated equivalents for standard increments between Kilocalorie (th)/kilogram/°C (kcal (th)/(kg·°C)) and Calorie (IT)/gram/°F (cal/(g·°F)).
| Conversion & Equivalent Value | Scientific Notation |
|---|---|
| 0.001 kcal (th)/(kg·°C) 0.0017988 cal/(g·°F) | 1.799 × 10⁻³ |
| 0.01 kcal (th)/(kg·°C) 0.017988 cal/(g·°F) | 1.799 × 10⁻² |
| 0.1 kcal (th)/(kg·°C) 0.17988 cal/(g·°F) | 1.799 × 10⁻¹ |
| 0.5 kcal (th)/(kg·°C) 0.899398 cal/(g·°F) | 8.994 × 10⁻¹ |
| 1 kcal (th)/(kg·°C) 1.798796 cal/(g·°F) | 1.799 × 10⁰ |
| 2 kcal (th)/(kg·°C) 3.597592 cal/(g·°F) | 3.598 × 10⁰ |
| 5 kcal (th)/(kg·°C) 8.993981 cal/(g·°F) | 8.994 × 10⁰ |
| 10 kcal (th)/(kg·°C) 17.987962 cal/(g·°F) | 1.799 × 10¹ |
| 20 kcal (th)/(kg·°C) 35.975924 cal/(g·°F) | 3.598 × 10¹ |
| 25 kcal (th)/(kg·°C) 44.969905 cal/(g·°F) | 4.497 × 10¹ |
| 50 kcal (th)/(kg·°C) 89.939811 cal/(g·°F) | 8.994 × 10¹ |
| 100 kcal (th)/(kg·°C) 179.879622 cal/(g·°F) | 1.799 × 10² |
| 250 kcal (th)/(kg·°C) 449.699054 cal/(g·°F) | 4.497 × 10² |
| 500 kcal (th)/(kg·°C) 899.398108 cal/(g·°F) | 8.994 × 10² |
| 1000 kcal (th)/(kg·°C) 1798.796217 cal/(g·°F) | 1.799 × 10³ |
| Reciprocal & Equivalent Value | Scientific Notation |
|---|---|
| 1 cal/(g·°F) 0.555927 kcal (th)/(kg·°C) | 5.559 × 10⁻¹ |
| 5 cal/(g·°F) 2.779637 kcal (th)/(kg·°C) | 2.78 × 10⁰ |
| 10 cal/(g·°F) 5.559273 kcal (th)/(kg·°C) | 5.559 × 10⁰ |
| 50 cal/(g·°F) 27.796367 kcal (th)/(kg·°C) | 2.78 × 10¹ |
| 100 cal/(g·°F) 55.592734 kcal (th)/(kg·°C) | 5.559 × 10¹ |
Real-World Context & Everyday Benchmarks
Tap to load into converterTo help contextualize these units in everyday life, science, and engineering, here are verified real-world reference points for Kilocalorie (th)/kilogram/°C (kcal (th)/(kg·°C)) and Calorie (IT)/gram/°F (cal/(g·°F)):
Kilocalorie (th)/kilogram/°C References:
- Pure liquid water standard specific heat capacity at 25°C 1 kcal (th)/(kg·°C)
- Dry atmospheric air specific heat at constant pressure cp 0.240201 kcal (th)/(kg·°C)
- Solid structural aluminum metal specific heat capacity 0.214388 kcal (th)/(kg·°C)
- Pure electrical copper metal specific heat capacity 0.092017 kcal (th)/(kg·°C)
Calorie (IT)/gram/°F References:
- Pure liquid water standard specific heat capacity at 25°C 1.7988 cal/(g·°F)
- Dry atmospheric air specific heat at constant pressure cp 0.432072 cal/(g·°F)
- Solid structural aluminum metal specific heat capacity 0.385641 cal/(g·°F)
- Pure electrical copper metal specific heat capacity 0.16552 cal/(g·°F)
How to Convert Kilocalorie (th)/kilogram/°C to Calorie (IT)/gram/°F
Converting Kilocalorie (th)/kilogram/°C (kcal (th)/(kg·°C)) to Calorie (IT)/gram/°F (cal/(g·°F)) is a core calculation in Specific Heat Capacity, which measures the thermal energy required to raise the temperature of a unit mass of substance by one degree. Because Kilocalorie (th)/kilogram/°C represents a larger magnitude than Calorie (IT)/gram/°F, converting from kcal (th)/(kg·°C) to cal/(g·°F) expands the numerical figure. Exactly 1 Kilocalorie (th)/kilogram/°C encompasses 1.798796 Calorie (IT)/gram/°F. To convert any quantity, multiply the value in Kilocalorie (th)/kilogram/°C by 1.798796.
Mathematical Conversion Derivation via Coherent SI Base Unit
Under the International System of Quantities (ISQ), dimensional conversion between non-SI units is rigorously resolved by bridging through the coherent SI base unit (joule per kilogram kelvin (J/(kg·K))) without arbitrary rounding:
1 kcal (th)/(kg·°C) = 4184 joule per kilogram kelvin (J/(kg·K))1 cal/(g·°F) = 2326 joule per kilogram kelvin (J/(kg·K))V(cal/(g·°F)) = V(kcal (th)/(kg·°C)) × ( 4184 / 2326 ) = V(kcal (th)/(kg·°C)) × 1.798796Value in Calorie (IT)/gram/°F = Value in Kilocalorie (th)/kilogram/°C × 1.79879622Direct computational formula applied for standard conversion.To convert 24 Kilocalorie (th)/kilogram/°C (kcal (th)/(kg·°C)) to Calorie (IT)/gram/°F (cal/(g·°F)): multiply 24 by 1.798796 to get 43.171109 cal/(g·°F). At an industrial engineering scale, 240 kcal (th)/(kg·°C) converts to 431.711092 cal/(g·°F).
Inverse check: 1 cal/(g·°F) = 0.555927 kcal (th)/(kg·°C).Understanding Kilocalorie (th)/kilogram/°C and Calorie (IT)/gram/°F
Kilocalorie (th)/kilogram/°C
kcal (th)/(kg·°C)A Kilocalorie (th)/kilogram/°C (kcal (th)/(kg·°C)) is a decimal multiple of the SI-derived unit for specific heat capacity.
Applications & Practical Context
In practical specific heat capacity terms, a pure liquid water standard specific heat capacity at 25°C equals 1 kcal (th)/(kg·°C), a dry atmospheric air specific heat at constant pressure cp equals 0.240201 kcal (th)/(kg·°C), a solid structural aluminum metal specific heat capacity equals 0.214388 kcal (th)/(kg·°C).
A physical magnitude of 1 kcal (th)/(kg·°C) corresponds to 4184 J/(kg·K) in standard SI measurement.
1 kcal (th)/(kg·°C) = 4184 J/(kg·K)Calorie (IT)/gram/°F
cal/(g·°F)A Calorie (IT)/gram/°F (cal/(g·°F)) is a recognized unit for specific heat capacity.
Applications & Practical Context
In practical specific heat capacity terms, a pure liquid water standard specific heat capacity at 25°C equals 1.7988 cal/(g·°F), a dry atmospheric air specific heat at constant pressure cp equals 0.432072 cal/(g·°F), a solid structural aluminum metal specific heat capacity equals 0.385641 cal/(g·°F).
A physical magnitude of 1 cal/(g·°F) corresponds to 2326 J/(kg·K) in standard SI measurement.
1 cal/(g·°F) = 2326 J/(kg·K)Domain Metrology & Engineering Applications
Specific Enthalpy Derivative (c_p = (∂h/∂T)_p)
Rigorously quantified in laboratory and field settings using differential scanning calorimeters (DSC), adiabatic drop calorimeters, and dual-furnace calorimeter systems.
Applied across battery thermal runaway mitigation (EV cell modeling), chemical synthesis reactor safety, molten salt solar storage, and cryogenic coolant engineering under international metrology standard ISO 80000-5:2019, NIST Chemistry WebBook.
Formulas, conversion coefficients, and base definitions on this page strictly adhere to the ISO 80000-5:2019, NIST Chemistry WebBook and the BIPM SI Brochure (9th Edition). Governed by Specific Enthalpy Derivative (c_p = (∂h/∂T)_p) under ISO 80000 dimensional vector [L² T⁻² Θ⁻¹].
Specific Heat Capacity to Thermal Energy Storage Bridge (Joules • Kilojoules • Megajoules • kWh • BTU)
Calculate total sensible thermal storage energy Q = c_p × (m × ΔT) for heating or cooling mass charges, bridging specific heat capacity [L² T⁻² Θ⁻¹] with stored thermal energy [M L² T⁻²].
Q = c_p × (m × ΔT)
[J/(kg·K)] × [kg·K] → [J]
-
1. Normalize Input to SI Base Unit (J/(kg·K)):
c_p = 1 kcal (th)/(kg·°C) × 4184 = 4184 J/(kg·K) -
2. Apply Engineering Parameter (mΔT):
Selected condition: 50 kg Domestic Water at 40K Swing (2,000 kg·K) at mΔT = 2000 kg·K -
3. Execute Governing Physical Law in SI Units:
Q = c_p × (m × ΔT) = (4184 J/(kg·K)) × (2000 kg·K) = 8368000 J -
4. Convert to Standard Engineering Units:
• J: 8368000 × 1 = 8368000 J (Joules) • kJ: 8368000 × 0.001 = 8368 kJ (Kilojoules) • MJ: 8368000 × 1 × 10⁻⁶ = 8.368 MJ (Megajoules) • kWh: 8368000 × 2.7778 × 10⁻⁷ = 2.324444 kWh (Kilowatt-Hours) • Wh: 8368000 × 0.0002778 = 2324.4444 Wh (Watt-Hours) • BTU: 8368000 × 0.0009478 = 7931.3337 BTU (British Thermal Units)
| Engineering Substance / Operating Standard | Parameter Value (kg·K) | Reference State / Condition | Typical Industrial & Engineering Application |
|---|---|---|---|
| 50 kg Domestic Water at 40K Swing (2,000 kg·K) | 2000 |
m = 50 kg, ΔT = 40 K | 50-liter domestic hot water tank charge |
| 1,000 kg Hydronic Buffer at 20K Swing (20,000 kg·K) | 20000 |
m = 1,000 kg, ΔT = 20 K | Commercial heat pump thermal buffer storage |
| 200 kg Engine Block at 70K Swing (14,000 kg·K) | 14000 |
m = 200 kg, ΔT = 70 K | Cast iron engine warm-up heat soak |
| 10,000 kg Process Fluid at 50K Swing (500,000 kg·K) | 500000 |
m = 10,000 kg, ΔT = 50 K | Industrial batch chemical reactor heat load |
Frequently Asked Questions
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