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Calories (it)/gram/°F to Joules/kilogram/K Converter (cal/(g·°F) to J/(kg·K))

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Live Conversion • ISO 80000-5:2019 Certified
1 Calorie (IT)/gram/°F = 2326 Joule/kilogram/K
1 cal/(g·°F) = 2,326 J/(kg·K) • 1 J/(kg·K) = 0.000429923 cal/(g·°F)
Calorie (IT)/gram/°F to Joule/kilogram/K: One Calorie (IT)/gram/°F is equal to 2326 Joules/kilogram/K.
Certified Authority Value
2326.00000000
J/(kg·K)
Exact: 1 J/(kg·K) ≡ 0.0004299226139 cal/(g·°F)
cal/(g·°F)
cal/(g·°F)
Swap to Joule/kilogram/K to Calorie (IT)/gram/°F
Swap to Joule/kilogram/K to Calorie (IT)/gram/°F
J/(kg·K)
J/(kg·K) 2326
Quick Values:
Conversion Formula
To convert Calorie (IT)/gram/°F to Joule/kilogram/K, multiply by 2326
cal/(g·°F) × 2326 = J/(kg·K)

Calculation: 1 cal/(g·°F) × 2326 = 2326 J/(kg·K)

Common Calorie (IT)/gram/°F to Joule/kilogram/K Calculations

Quick-lookup reference table showing calculated equivalents for standard increments between Calorie (IT)/gram/°F (cal/(g·°F)) and Joule/kilogram/K (J/(kg·K)).

Tap any row to calculate
Calorie (IT)/gram/°F to Joule/kilogram/K: Primary Direct Table (15 Steps)
Calorie (IT)/gram/°F to Joule/kilogram/K Conversion Reference Table
Conversion & Equivalent Value Scientific Notation
0.001 cal/(g·°F) 2.326 J/(kg·K) 2.326 × 10⁰
0.01 cal/(g·°F) 23.26 J/(kg·K) 2.326 × 10¹
0.1 cal/(g·°F) 232.6 J/(kg·K) 2.326 × 10²
0.5 cal/(g·°F) 1163 J/(kg·K) 1.163 × 10³
1 cal/(g·°F) 2326 J/(kg·K) 2.326 × 10³
2 cal/(g·°F) 4652 J/(kg·K) 4.652 × 10³
5 cal/(g·°F) 11630 J/(kg·K) 1.163 × 10⁴
10 cal/(g·°F) 23260 J/(kg·K) 2.326 × 10⁴
20 cal/(g·°F) 46520 J/(kg·K) 4.652 × 10⁴
25 cal/(g·°F) 58150 J/(kg·K) 5.815 × 10⁴
50 cal/(g·°F) 116300 J/(kg·K) 1.163 × 10⁵
100 cal/(g·°F) 232600 J/(kg·K) 2.326 × 10⁵
250 cal/(g·°F) 581500 J/(kg·K) 5.815 × 10⁵
500 cal/(g·°F) 1163000 J/(kg·K) 1.163 × 10⁶
1000 cal/(g·°F) 2326000 J/(kg·K) 2.326 × 10⁶
Joule/kilogram/K to Calorie (IT)/gram/°F: Reciprocal Summary
Joule/kilogram/K to Calorie (IT)/gram/°F Conversion Reference Table
Reciprocal & Equivalent Value Scientific Notation
1 J/(kg·K) 0.000429923 cal/(g·°F) 4.299 × 10⁻⁴
5 J/(kg·K) 0.00214961 cal/(g·°F) 2.15 × 10⁻³
10 J/(kg·K) 0.00429923 cal/(g·°F) 4.299 × 10⁻³
50 J/(kg·K) 0.0214961 cal/(g·°F) 2.15 × 10⁻²
100 J/(kg·K) 0.0429923 cal/(g·°F) 4.299 × 10⁻²
View Complete 15-Row Joule/kilogram/K to Calorie (IT)/gram/°F Table

Real-World Context & Everyday Benchmarks

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To help contextualize these units in everyday life, science, and engineering, here are verified real-world reference points for Calorie (IT)/gram/°F (cal/(g·°F)) and Joule/kilogram/K (J/(kg·K)):

Calorie (IT)/gram/°F References:

  • Pure liquid water standard specific heat capacity at 25°C 1.7988 cal/(g·°F)
  • Dry atmospheric air specific heat at constant pressure cp 0.432072 cal/(g·°F)
  • Solid structural aluminum metal specific heat capacity 0.385641 cal/(g·°F)
  • Pure electrical copper metal specific heat capacity 0.16552 cal/(g·°F)

Joule/kilogram/K References:

  • Pure liquid water standard specific heat capacity at 25°C 4184 J/(kg·K)
  • Dry atmospheric air specific heat at constant pressure cp 1005 J/(kg·K)
  • Solid structural aluminum metal specific heat capacity 897 J/(kg·K)
  • Pure electrical copper metal specific heat capacity 385 J/(kg·K)

Tap any benchmark above to automatically calculate its exact equivalent in Joule/kilogram/K.

ISQ Dimension: [L² T⁻² Θ⁻¹] Coherent SI Unit: joule per kilogram kelvin (J/(kg·K)) Thermodynamics & Heat Transfer

How to Convert Calorie (IT)/gram/°F to Joule/kilogram/K

Converting Calorie (IT)/gram/°F (cal/(g·°F)) to Joule/kilogram/K (J/(kg·K)) is a core calculation in Specific Heat Capacity, which measures the thermal energy required to raise the temperature of a unit mass of substance by one degree. Because Calorie (IT)/gram/°F represents a larger magnitude than Joule/kilogram/K, converting from cal/(g·°F) to J/(kg·K) expands the numerical figure. Exactly 1 Calorie (IT)/gram/°F encompasses 2326 Joule/kilogram/K. To convert any quantity, multiply the value in Calorie (IT)/gram/°F by 2326.

Direct Factor1 cal/(g·°F) = 2326 J/(kg·K)
Inverse Ratio1 J/(kg·K) = 0.000429923 cal/(g·°F)
Conversion ScaleDirect Proportional Magnitude Expansion
First-Principles SI Derivation ProofNIST SP 811 / ISO 80000 Compliance

Mathematical Conversion Derivation via Coherent SI Base Unit

Under the International System of Quantities (ISQ), dimensional conversion between non-SI units is rigorously resolved by bridging through the coherent SI base unit (joule per kilogram kelvin (J/(kg·K))) without arbitrary rounding:

Vtarget=Vsource×(ksource→SIktarget→SI)V_{\text{target}} = V_{\text{source}} \times \left( \frac{k_{\text{source} \to \text{SI}}}{k_{\text{target} \to \text{SI}}} \right)
Universal Dimensional Conversion Law (ISO 80000 / NIST SP 811)
1. Source SI Bridge (ksource):1 cal/(g·°F) = 2326 joule per kilogram kelvin (J/(kg·K))
2. Target SI Bridge (ktarget):1 J/(kg·K) = 1 joule per kilogram kelvin (J/(kg·K))
Step-by-step substitution for Calorie (IT)/gram/°F → Joule/kilogram/K:V(J/(kg·K)) = V(cal/(g·°F)) × ( 2326 / 1 ) = V(cal/(g·°F)) × 2326
Mathematical FormulaValue in Joule/kilogram/K = Value in Calorie (IT)/gram/°F × 2326Direct computational formula applied for standard conversion.
Worked Example

For an engineering input of 8 cal/(g·°F), applying the conversion factor yields exactly 18608 J/(kg·K). At larger operational scale, 100 Calorie (IT)/gram/°F corresponds to 232600 J/(kg·K).

Inverse check: 1 J/(kg·K) = 0.000429923 cal/(g·°F).

Understanding Calorie (IT)/gram/°F and Joule/kilogram/K

Calorie (IT)/gram/°F

cal/(g·°F)
Standard Unit

A Calorie (IT)/gram/°F (cal/(g·°F)) is a recognized unit for specific heat capacity.

Applications & Practical Context

In practical specific heat capacity terms, a pure liquid water standard specific heat capacity at 25°C equals 1.7988 cal/(g·°F), a dry atmospheric air specific heat at constant pressure cp equals 0.432072 cal/(g·°F), a solid structural aluminum metal specific heat capacity equals 0.385641 cal/(g·°F).

Physical Setup

A physical magnitude of 1 cal/(g·°F) corresponds to 2326 J/(kg·K) in standard SI measurement.

Conversion to SI Unit: joule per kilogram kelvin (J/(kg·K))
1 cal/(g·°F) = 2326 J/(kg·K)

Joule/kilogram/K

J/(kg·K)
Standard Unit

A Joule/kilogram/K (J/(kg·K)) is a recognized unit for specific heat capacity.

Applications & Practical Context

In practical specific heat capacity terms, a pure liquid water standard specific heat capacity at 25°C equals 4184 J/(kg·K), a dry atmospheric air specific heat at constant pressure cp equals 1005 J/(kg·K), a solid structural aluminum metal specific heat capacity equals 897 J/(kg·K).

Physical Setup

A specific heat capacity of 1 J/(kg·K) means 1 Joule/kilogram/K of heat energy changes the temperature of 1 unit mass by 1 degree.

Conversion to SI Unit: joule per kilogram kelvin (J/(kg·K))
1 J/(kg·K) = 1 J/(kg·K)

Domain Metrology & Engineering Applications

Governing Law & Equation

Specific Enthalpy Derivative (c_p = (∂h/∂T)_p)

Measurement Instrumentation

Rigorously quantified in laboratory and field settings using differential scanning calorimeters (DSC), adiabatic drop calorimeters, and dual-furnace calorimeter systems.

Primary Industry Sectors

Applied across battery thermal runaway mitigation (EV cell modeling), chemical synthesis reactor safety, molten salt solar storage, and cryogenic coolant engineering under international metrology standard ISO 80000-5:2019, NIST Chemistry WebBook.

Institutional Metrology & Standard Authority:

Formulas, conversion coefficients, and base definitions on this page strictly adhere to the ISO 80000-5:2019, NIST Chemistry WebBook and the BIPM SI Brochure (9th Edition). Governed by Specific Enthalpy Derivative (c_p = (∂h/∂T)_p) under ISO 80000 dimensional vector [L² T⁻² Θ⁻¹].

Multi-Variable Engineering Bridge Thermodynamics & Heat Storage

Specific Heat Capacity to Thermal Energy Storage Bridge (Joules • Kilojoules • Megajoules • kWh • BTU)

Calculate total sensible thermal storage energy Q = c_p × (m × ΔT) for heating or cooling mass charges, bridging specific heat capacity [L² T⁻² Θ⁻¹] with stored thermal energy [M L² T⁻²].

Q = c_p × (m × ΔT)
Vector: [J/(kg·K)] × [kg·K] → [J]
Live Calculated Bridge Equivalent:
1 cal/(g·°F) at 50 kg Domestic Water at 40K Swing (2,000 kg·K) = 4652000 J
Equals 4652 kJ • 4.652 MJ • 1.292222 kWh
SI Energy
4652000
J
Joules
Thermal Scale
4652
kJ
Kilojoules
Bulk Energy
4.652
MJ
Megajoules
Electric Utility Meter
1.292222
kWh
Kilowatt-Hours
Battery Capacity
1292.2222
Wh
Watt-Hours
Imperial Thermal
4409.2452
BTU
British Thermal Units
  1. 1. Normalize Input to SI Base Unit (J/(kg·K)):
    c_p = 1 cal/(g·°F) × 2326 = 2326 J/(kg·K)
  2. 2. Apply Engineering Parameter (mΔT):
    Selected condition: 50 kg Domestic Water at 40K Swing (2,000 kg·K) at mΔT = 2000 kg·K
  3. 3. Execute Governing Physical Law in SI Units:
    Q = c_p × (m × ΔT) = (2326 J/(kg·K)) × (2000 kg·K) = 4652000 J
  4. 4. Convert to Standard Engineering Units:
    • J: 4652000 × 1 = 4652000 J (Joules) • kJ: 4652000 × 0.001 = 4652 kJ (Kilojoules) • MJ: 4652000 × 1 × 10⁻⁶ = 4.652 MJ (Megajoules) • kWh: 4652000 × 2.7778 × 10⁻⁷ = 1.292222 kWh (Kilowatt-Hours) • Wh: 4652000 × 0.0002778 = 1292.2222 Wh (Watt-Hours) • BTU: 4652000 × 0.0009478 = 4409.2452 BTU (British Thermal Units)
Explore Full Energy Converter →
Engineering Substance / Operating Standard Parameter Value (kg·K) Reference State / Condition Typical Industrial & Engineering Application
50 kg Domestic Water at 40K Swing (2,000 kg·K) 2000 m = 50 kg, ΔT = 40 K 50-liter domestic hot water tank charge
1,000 kg Hydronic Buffer at 20K Swing (20,000 kg·K) 20000 m = 1,000 kg, ΔT = 20 K Commercial heat pump thermal buffer storage
200 kg Engine Block at 70K Swing (14,000 kg·K) 14000 m = 200 kg, ΔT = 70 K Cast iron engine warm-up heat soak
10,000 kg Process Fluid at 50K Swing (500,000 kg·K) 500000 m = 10,000 kg, ΔT = 50 K Industrial batch chemical reactor heat load
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Frequently Asked Questions

There are exactly 2326 joules/kilogram/k (J/(kg·K)) in 1 calorie (it)/gram/°f (cal/(g·°F)). To calculate larger amounts manually, simply multiply your total number of calories (it)/gram/°f by the conversion multiplier of 2326.

The mathematical formula to convert calories (it)/gram/°f to joules/kilogram/k is: [value] * 2326 = joules/kilogram/k. Rather than doing the math manually, you can use our high-precision online calculator to process this exact equation instantly without rounding errors.

To perform the reverse calculation from joules/kilogram/k back to calories (it)/gram/°f, you must divide your starting value by 2326. Our bidirectional tool automatically computes this inverse equation the moment you type into the joule/kilogram/k input field.

1 Calorie (IT)/gram/°F is larger than 1 Joule/kilogram/K. Specifically, 1 Calorie (IT)/gram/°F equals exactly 2326 joules/kilogram/k, making it 2326 times larger (a difference of 3.37 orders of magnitude). Therefore, quantities expressed in joules/kilogram/k require a larger numerical value to represent the same physical amount.

Under standard international measurement guidelines, 1 Calorie (IT)/gram/°F converts to 2326 joules/kilogram/k. Precise numerical conversion factors ensure consistency across laboratory, engineering, and field data.