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Specific Heat Capacity Conversion Hub

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Live Conversion • ISO 80000-5:2019 Certified
1 Joule/kilogram kelvin = 1 Joule/kilogram celsius
1 J/(kg·K) = 1 J/(kg·°C) • 1 J/(kg·°C) = 1 J/(kg·K)
Joule/kilogram kelvin to Joule/kilogram celsius: One Joule/kilogram kelvin is equal to 1 Joule/kilogram celsius.
Certified Authority Value
1.0000
J/(kg·°C)
Exact: 1 J/(kg·°C) ≡ 1 J/(kg·K)
J/(kg·K)
J/(kg·K)
J/(kg·°C)
J/(kg·°C) 1
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Understanding Specific Heat Capacity & Thermal Inertia

Specific heat capacity (denoted as c or cpc_p) measures the quantity of thermal energy required to raise the temperature of a unit mass of a substance by one unit of temperature. It reflects a substance's intrinsic thermal inertia—materials with high specific heat (like liquid water, c≈4,184 J/(kg⋅K)c \approx 4,184\text{ J}/(\text{kg}\cdot\text{K})) require immense energy to warm up and release substantial energy during cooling.

Thermodynamic Laws & Constant Volume vs Constant Pressure

Thermal energy absorbed or released during sensible heating without phase change is calculated as:

Q=m⋅cp⋅ΔTQ = m \cdot c_p \cdot \Delta T

For gases and compressible fluids, thermodynamics distinguishes between specific heat at constant pressure (cpc_p) and constant volume (cvc_v), governed by Mayer's relation for ideal gases: cp−cv=Rspecificc_p - c_v = R_{specific}. Their ratio, the adiabatic index γ=cpcv\gamma = \frac{c_p}{c_v}, dictates the speed of sound and isentropic expansion in nozzles and turbines.

Standard Units & Metric Multipliers

  • SI Metric: Joule per kilogram kelvin (J/(kg⋅K)\text{J}/(\text{kg}\cdot\text{K})) or joule per kilogram degree Celsius (J/(kg⋅∘C)\text{J}/(\text{kg}\cdot^\circ\text{C})). $1\text{ J}/(\text{kg}\cdot\text{K}) = 1\text{ J}/(\text{kg}\cdot^\circ\text{C})$.
  • Imperial Engineering: BTU per pound degree Fahrenheit (BTU/(lb⋅∘F)\text{BTU}/(\text{lb}\cdot^\circ\text{F})). $1\text{ BTU}/(\text{lb}\cdot^\circ\text{F}) \approx 4,186.8\text{ J}/(\text{kg}\cdot\text{K})$. Notice that water's specific heat is exactly $1.0\text{ BTU}/(\text{lb}\cdot^\circ\text{F}) = 1.0\text{ cal}/(\text{g}\cdot^\circ\text{C})$.
  • CGS Caloric: Calorie per gram degree Celsius (cal/(g⋅∘C)\text{cal}/(\text{g}\cdot^\circ\text{C})). $1\text{ cal}/(\text{g}\cdot^\circ\text{C}) = 4,184\text{ J}/(\text{kg}\cdot\text{K})$.

Engineering Applications

Crucial for selecting coolant fluids in internal combustion engines and EV battery packs, designing thermal energy storage (TES) systems with molten salts, and sizing thermal mass in passive solar architecture.

Frequently Asked Questions

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